C'mon, guys!

[David J. Fiander]

>> So an array is not a pointer but a reference to an array
>> in an expression is a pointer.
>
>That's part of it, but I strongly suspect that people have been confused by
>the fact that when you use an array name in an expression it really means a
>pointer to the first member of the array; they interpret this limited
>interchangability as meaning pointers and arrays are equivalent.

I discovered a very simple way to thing of the name of an array: think of
it a a constant.  That's how the compiler treats it at least, and that is
why the expression:
		
			{
			int a[10], *ptr;

			ptr = &a;
			}

is invalid, you can't take the address of a macro (which the name of
the array is to the compiler.

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