Re^2: QuickC

[Leif Andrew Rump]

TURGUT at TREARN.BITNET (Turgut Kalfaoglu) writes:
>square(num)
>int num;
>{
>  num = num*num;
>}

>OK? There is no 'return' statement in the function. However, it works!
>I get '4' as an answer. So I thought maybe it was keeping the result
>of the last operation, so I added some dummy lines,

>square(num)
>int num;
>{
>  int dummy;
>  num = num*num;
>  dummy=222;
>}

>but the call STILL works... Can anyone shed some light onto this?
>WHY does it work?

My answer has not been tested but I'm quite sure that this is the
right answer to your question:

When you call a function i C the parameters is put on the stack. You
function uses the stack to keep the variable num and when the function
return the result is popped from the stack - which (unfortunately(!)
is the temporary variable num! 

   Leif Andrew Rump, Ambrasoft A/S, Roejelskaer 15, DK-2840 Holte (Denmark)
 UUCP: leif at ambone.dk, phone: +45 2424 111; ABC BBS: +45 68 00 544 (2:505/38)

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