Evaluation order of assignment.

[Liber]

In article <957 at orion.cf.uci.edu> schmidt at bonnie.ics.uci.edu (Douglas C. Schmidt) writes:

>Is the following always guaranteed to produce the "intended" result:

>[...]
>   return(head->next = head = (struct list *) malloc(sizeof(struct list)));

>Since assignment associates from right-to-left this
>will alway work, right (cryptic style notwithstanding !! ;-)).

No (you should probably get a compiler warning).  Although assignment
*associates* from right-to-left, assignment does not (necessarily)
*evaluate* from right-to-left.  All that associativity means is that

	(a) = (b) = (c);

(where a, b, c are expressions and a,b both produce lvalues) is
equivalent to

	( (a) = ( (b) = (c) ) );

and not

	( ( (a) = (b) ) = (c) );

order of evaluation of the expressions a, b, c is still undefined.
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