In article <1797 at dataio.Data-IO.COM> bright at dataio.Data-IO.COM (Walter Bright) writes:
>But doesn't sizeof('\0') return sizeof(int), instead of sizeof(char)?
Yes ...
>Remember, the integral promotions are being done.
... but integral promotion has nothing to do with it. '\0' IS an integer
constant of value 0 and type int, not char.