unsigned int assigned to double yields negative # ... Why?

[Michael T Sullivan]

In article <5020 at nsc.nsc.com>, andrew at nsc.nsc.com (Andrew Lue) writes:
> {
> unsigned int ui = 0xf0000000;
> double d;
> 
> d = ui;
> printf("%d\n");
> }
> 
> The books by K&R and Harrison & Steele are unclear about how this conversion
> should be applied.  Does anyone know what the definitive conversion is?
> Or is the decision left up to the compiler writers?

Why leave the decision up to the compiler writers?  Cast ui:

	d = (double)ui;

Don't rely on what you think may happen if the compiler happens to be
what you expect it to be.

good
food
yum
yum
yum

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