swap(x,y)
Wolfgang Deifel
wolfgang at ruso.UUCP
Mon Aug 28 18:32:04 AEST 1989
pmaniac at walt.cc.utexas.edu (Noah Friedman) writes:
>void swap(double *x, double *y)
>{
> *x += *y;
> *y = *x - *y;
> *x -= *y;
>}
>func()
>{
> int a, b;
> ...
> swap((double *) &a, (double *) &b);
> ...
>}
I think, this function never works right. If you cast the adress of
an integer to adress of double, you don't cast the int to double.
What you wanted to do is ( I think ), &((double)a) but this also
doesn't work, because (double)a is an r-value which has no adress.
--
Wolfgang Deifel
Dr. Ruff Software GmbH, 5100 Aachen, Juelicherstr. 65-67, W-Germany
uucp: ...!uunet{!mcvax}!unido!rwthinf!ruso!wolfgang - phone : +49 241 156038
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