An interesting behaviour in printf

[Andrew Koenig]

In article <960 at Portia.Stanford.EDU>, joe at hanauma (Joe Dellinger) writes:

> What would you expect the following program to print out?

> 	#include <stdio.h>
> 	main()
> 	{
> 	char string[10];
> 	string[0] = '*';
> 	string[1] = '\0';
> 	printf("%s\n", string[1]);
> 	}

The program is invalid; the implementation is allowed to
do as it pleases.

You said

	string[1] = '\0';

which is equivalent to

	string[1] = 0;

and then said

	printf("%s\n", string[1]);

which is, of course, equivalent to

	printf("%s\n", 0);

This asks printf to print characters starting at memory location 0;
not quite what you probably wanted.

Try this:

	printf("%s\n", &string[1]);

or, equivalently, this:

	printf("%s\n", string+1);
-- 
				--Andrew Koenig
				  ark at europa.att.com