/ eecs.nwu.edu:comp.lang.c / pathak at s.cs.uiuc.edu / 8:44 pm Mar 10, 1989 /
> main(n,m){for(scanf("%d",&m);m>1&m<10;n*=m--);
> printf(m-1?"error\n":"answer is %d\n",n);}
The expression "m>1&m<10" can be optimized by one character with the
expression "m>1^m>9".
> Heeren Pathak
> s.cs.uiuc.edu
> zaphod.ncsa.uiuc.edu