printf in dump routine

[Michael Figg]

-----------------------------------------------------------------

Following is the relevent piece of code from a dump routine I have been 
trying to write on an Amiga. I'm trying to pass a pointer to a variable
that I want to dump in hex and the number of bytes to print:
  
    .
    .
    long  test_long;
    test_long = 1234;
    print_data((char *)&test_long,sizeof(test_long));
    .  
    .
    void print_data(pnt,num)
    char *pnt;
    int num;
    {
      int i;
      for(i = 0; i < num; i++)
      {
	 printf("%02x",*(pnt + i));
      }
    }
    .
    What I would hope to get from this is '000004d2' but actually got 
    '000004ffffffd2'. This was done with Lattice v5.0.1. I also tried 
    similar code at work on a PC with MS v5.1. There I got 'ffd2040000',
    which except for the leading 'ff' looks like it was printing the bytes
    backwards. Any clues as to why I'm getting this output and how to do it
    right?  Thanks
						->Mike<-



-- 
"Hot Damn! Groat Cakes Again                   Michael Figg
Heavy on the thirty weight!"                   DLA Systems Automation Center
                                               Columbus, Oh.
                                               (614)-238-9036