casts and assignments
Wade Guthrie
evil at arcturus.UUCP
Thu Nov 30 07:56:22 AEST 1989
Let me display my ignorance here: from reading various things posted on the net,
I am led to believe that all assignments include an implicit cast such that:
a = (type of 'a') (expression);
Is exactly equivalent in ALL cases to:
a = (expression);
Is this true?
Wade Guthrie
evil at arcturus.UUCP
Rockwell International
Anaheim, CA
(Rockwell doesn't necessarily believe / stand by what I'm saying; how could
they when *I* don't even know what I'm talking about???)
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