on the fringe of C syntax/semantics
Wm E Davidsen Jr
davidsen at crdos1.crd.ge.COM
Wed Oct 11 03:31:53 AEST 1989
In article <457 at usage.csd.unsw.oz>, troy at mr_plod.cbme.unsw.oz (Troy Rollo) writes:
| From article <789 at crdos1.crd.ge.COM>, by davidsen at crdos1.crd.ge.COM (Wm E Davidsen Jr):
|
| davidsen> If I understand the question, you want (int(*)())
|
| Nope - bracketing only works when you have something to group with. that will
| produce exactly the same results as (int *())
In the original question some aspect of varargs was being questioned, in
which the argument in question is used as a cast. This is how a cast
works:
(int (*)()) cast X into pointer to function returning int
(int *()) cast X into function returning pointer to int
I realize that the macro may not be identical on all systems, but I
*thought* that's what the std said, a type, formatted to be used as a
cast. Used *as I indicated* the expressions do not have the same effect
at all and I'm not sure that the 2nd is legal, casting something to be a
function???
--
bill davidsen (davidsen at crdos1.crd.GE.COM -or- uunet!crdgw1!crdos1!davidsen)
"The world is filled with fools. They blindly follow their so-called
'reason' in the face of the church and common sense. Any fool can see
that the world is flat!" - anon
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