log10(8)

[Michael Meissner]

In article <1460 at amethyst.math.arizona.edu> raw at math.arizona.edu (Rich
Walters) writes:

| In article <3244 at servax0.essex.ac.uk> elzea at sersun0.essex.ac.uk (El-Zein A A) writes:
| >
| >	My calculator gives me 0.9030899 for log(8),
| >	While the following code (which I thought would
| >	give me the above value of 0.9030899) prints 
| >	-312.770165.
| >
| >	double l;
| >	.
| >	l = log10(8);
| >	printf("%f", l);
| >       .
| >
| >	Can anybody tell me why.
| >
| 
| Try printf"%lf",l);  after all l is declared to be a double!!!!!!!!

Sigh.  Printf is a varargs function.  This means that there is no way
a 'float' can be passed to it.  Thus %f and %lf are synomous.....
--
Michael Meissner	email: meissner at osf.org		phone: 617-621-8861
Open Software Foundation, 11 Cambridge Center, Cambridge, MA

Catproof is an oxymoron, Childproof is nearly so