clock on the IBM (MSC)??? :-(

[Kianusch Sayah-Karadji]

I've got a problem...

My program should read in the keyboard and print it (or do something else)
and while it is doing this, it should display a clock on the screen (interrupt)!

clock works untill I read something from the keyboard.... Yuk!

I get a run-time error R6000... (Stack overflow)

the program is in C for the IBM (Microsof 5.1)...

HELP!!!
thanx....
					Kianusch 

----- program ----

#include <stdlib.h>
#include <stdio.h>
#include <dos.h>


void	cdecl interrupt far new_break(void);
void	(cdecl interrupt far *old_break)(void);
void	cdecl interrupt far new_tick(void);
void	(cdecl interrupt far *old_tick)(void);

void	gettime (char *, char *, char *);
void	set_interrupt (void);
void	bye(void);


char hr, min, sec, buf[11];
int count=0, inclock=0;

main()
{
    unsigned char ch;

    set_interrupt();

    do {
	ch = getchar();
	putchar (ch);
    } while (ch != 13);

    bye();
}


void set_interrupt(void)
{
    _disable();
	old_tick  = _dos_getvect(0x08);
	old_break = _dos_getvect(0x23);
	_dos_setvect (0x08, new_tick);
	_dos_setvect (0x23, new_break);
    _enable();

    gettime (&hr, &min, &sec);
}


void bye (void)
{
    _disable();

	_dos_setvect (0x23, old_break);
	_dos_setvect (0x08, old_tick);

    _enable();

    exit (1);
}
void cdecl interrupt far new_tick(void)
{
    if (!inclock) {
	inclock = 1;
	if (!count) {
	    count = (((sec%5)==0) ? 19 : 18);
	    if (++sec >= 60) {
		sec=0;
		if (++min >= 60) {
		    min=0;
		    if (++hr >= 24)
			hr = 0;
		}
	    }
	    printf(buf, " %02d:%02d:%02d ", hr, min, sec);
	    /* printf for simplicity */
	}
	--count;
	inclock = 0;
    }

    _chain_intr (old_tick);
}




void cdecl interrupt far new_break()
{
    bye(); 
}


void gettime (tmp_hr, tmp_min, tmp_sec)
char *tmp_hr, *tmp_min, *tmp_sec;
{
    union REGS regs;

    regs.h.ah = 0x2c;

    int86 (0x21, &regs, &regs);

    *tmp_hr  = regs.h.ch;
    *tmp_min = regs.h.cl;
    *tmp_sec = regs.h.dh;
}