IsUnsigned function? [A solution which almost works!]

[Mark Lanzo]

My boss thought this one up:

	#define IsUnsigned(x) (!( (x) < 0 || (-(x) < 0) ))

This will work, as long as "x" is a nonzero value.

At least this one tries to answer the actual question "Is it unsigned?" and
not "is it negative?" or "is the m.s.b. set?" ...


-- 
Mark Lanzo                      Wandel & Goltermann Technologies, Inc.
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