# TO THE NTH POWER

[Robbie Matthews]

Original to: blambert at lotus.com
OK. Here is a way of getting an integer root that I haven't seen yet:
 
 for (sqrtx=1, j=1, k=1; j<x; sqrtx+=1, k+=2, j+=k );
 
Try it and see. Only works for positive integers, but as there is no
multiplication or division, works reasonably fast. Especially on a 8 bit
machine.
 Not claiming it's a _better_ way... it's just a way.

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