why is free() a void?

[Karl Heuer]

In article <130 at nazgul.UUCP> bright at nazgul.UUCP (Walter Bright) writes:
>Thus, it became apparent that the abort should be moved inside of free().
>That's what the Zortech free function does now, if it detects a corrupted
>heap it prints the message:
>	"Heap is corrupted"
>and immediately terminates the program. free() now returns a void.

Good for you.  I hope you die with abort() or equivalent rather than exit()
(even if the distinction is minor under DOS); then you can answer the diehards
by telling them to trap SIGABRT.

Karl W. Z. Heuer (karl at ima.isc.com or uunet!ima!karl), The Walking Lint