Assignment Ops and Side Effects

[Checkpoint Technologies]

In article <1991Apr4.202314.961 at csrd.uiuc.edu> bliss at sp64.csrd.uiuc.edu (Brian Bliss) writes:
>P.S. an interesting tidbit I just found out:
>if you're on a machine where sizeof (int) == 4, then
>
>char ch;
>sizeof (ch += 1) == 4
>sizeof (ch++) == 1
>
>apparrently operands of ++ and -- do not undergo integral promotion

Is this really true?  Is it standard?

Does this means that if ch = 0xff (unsigned, 8 bit char), then i =
(++ch) assigns 0 to i (since the increment caused it to overflow)?
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