print % in c

[Richard A. O'Keefe]

In article <1991Feb25.180600.5004 at ux1.cso.uiuc.edu>, gordon at osiris.cso.uiuc.edu (John Gordon) writes:
> 	To print special characters with printf(), precede the character
> with a \ character.  Example:

> 	printf("This a percent sign: \%\n");
> 	printf("This is a backslash: \\\n");

Did you *try* this?  Backslash is handled by one of the compiler
phases.  The string "This is a percent sign \%\n" turns into the
characters <T,h,i,s, ,i,s, ,a, ,p,e,r,c,e,n,t, ,s,i,g,n, ,%,NEWLINE>
and by the time printf() sees it there is nothing special about the
percent sign.  To get a percent sign from printf(), use two % signs:
	printf("The original answer was 100%% wrong.\n");
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