Array question

[Thomas K. Kwong]

In article <EbhAAgG00WBNM2PIt_ at andrew.cmu.edu> rg2c+ at andrew.cmu.edu (Robert Nelson Gasch) writes:
>
>    int *this_ptr;
>    this_ptr [0] = 1;
>    this_ptr [1] = 2;
>    . . . 
>    this_ptr [9] = 10;
>
>This works fine, but I really don't know why?? It seems you're using
>memory to store an array which was never really allocated. If anybody
>could briefly explain what exactly happens when you do this, I'd be
>greatly abliged as at this point I'm mystified. 

An array subscript is really a shorthand of a pointer notation:
	a[i]   is exactly the same as    *(a+i)
This conversion is done in compile time, so what you're doing is just
using the space allocated in previous malloc() statement.

-Thomas.

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