Array question

[Xiang-Min Wang]

In article <9304 at hub.ucsb.edu> tomkwong at banana.UUCP (Thomas K. Kwong) writes:
>In article <EbhAAgG00WBNM2PIt_ at andrew.cmu.edu> rg2c+ at andrew.cmu.edu (Robert Nelson Gasch) writes:
>>
>>    int *this_ptr;
>>    this_ptr [0] = 1;
>>    this_ptr [1] = 2;
>>    . . . 
>>    this_ptr [9] = 10;
>>
>>This works fine, but I really don't know why?? It seems you're using
>>memory to store an array which was never really allocated. 

Please notice that althouhg the pointer 'this_ptr', after declared, is 
not initialized by YOU (I am not sure the C compiler will initialize 
it to zero or not), it bears some value (as an address) ANYWAY. 
Therefore, you can do the "normal" things to it like the assignment:

	this_ptr[i] = i (or *(this_ptr+i) = i )

Simply speaking, your program is SYNTACTICALLY correct, but FUNCTIONALLY
wrong.

xwang

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