why p->member ?

[John Peters]

In article <16734 at adm.ARPA>, stanonik at nprdc.arpa (Ron Stanonik) writes:
> While explaining pointers to structures someone asked why
> the -> operator was needed; ie, why couldn't the members be
> referenced as p.member.

It needs to be referenced as a pointer.  To do that use:

		*p.member

it is the same as

		p->member

				--  Johnnie  --