How does a program get its path name?
Chris Calabrese[rs]
cjc at ulysses.homer.nj.att.com
Tue Feb 23 02:56:12 AEST 1988
In article <2933 at sdsu.UUCP>, turtle at sdsu.UUCP writes:
>
> When a program executes, the full path to the executable file is kept in
> the zero-th argument. If you have a declaration of main which looks like this:
> main(argc,argv)
> int argc;
> char *argv[];
>
> then argv[0] is a pointer to the full path.
> Is this what you were looking for?
This is true only if the program was not found in the
current working directory, in which case argv[0] will contain
only the name of the program, not the full path. Of course,
you can test to see if argv[0][0] != '/' and getcwd()
to find the full path name.
Christopher Calabrese
AT&T Bell Laboratories
ulysses!cjc
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