extracting "rest of line" in AWK
Mark Bader
mbader at cac.washington.edu
Fri Aug 25 14:03:30 AEST 1989
Does anyone know of a way to extract the "rest of the line" in awk..
e.g. I have a line that looks like
%% Heading "This is a Graph Heading"
and I want to do a {print $3} to get the "This is a Graph Heading" part,
but this obviously dosen't work. Is there a way to do this?
If there were a shift command, then I could shift off the first 2 fields,
but is there a way to simulate this?
Thanks in advance,
Mark Bader INTERNET: mbader at cac.washington.edu
Networks and Distributed Computing, UW BITNET: mbader at uwav1
3737 Brooklyn Ave. NE BELL: (206) 543-5128
Seattle, WA 98105
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