Listing files bet. two specified dates

[Randal Schwartz]

In article <1990Oct24.181321.23205 at dg-rtp.dg.com>, rice at dg-rtp (Brian Rice) writes:
| #!/bin/sh
| # mbetween path bound_1 bound_2
| # Argument 1 is taken to be the root of the directory tree to 
| # search.  Argument 2 is one bound (in days), and argument 
| # 3 is the other bound (in days).
| 
| find $1 -mtime -$2 -print > /tmp/mbetween.$$
| find $1 -mtime -$3 -print >> /tmp/mbetween.$$
| 
| sort /tmp/mbetween.$$ > /tmp/mbetween2.$$
| uniq -u /tmp/mbetween2.$$
| 
| rm -f /tmp/mbetween.$$ /tmp/mbetween2.$$
| exit 0

Long way.  Try:

find $1 -mtime -$2 -mtime +$3 -print

with $2 and $3 being in the right order.  Much faster, and not prone
to phase errors.

I'd give you a Perl solution, but there's no point unless you want
finer granularity than one day.

Just another UNIX hacker,
-- 
/=Randal L. Schwartz, Stonehenge Consulting Services (503)777-0095 ==========\
| on contract to Intel's iWarp project, Beaverton, Oregon, USA, Sol III      |
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