The "if ( -e filename )" blues...
Jonathan I. Kamens
jik at cats.ucsc.edu
Tue Jun 18 08:12:14 AEST 1991
In article <1991Jun17.195519.12713 at murdoch.acc.Virginia.EDU>, eas at turing.acs.virginia.edu (Edward A. Schwab) writes:
|> Help! I'm trying to run a simple csh shell file that sets $OUT.out to an
|> output filename and $PROG to a program name, will search for $OUT.out, and
|> delete it... I'm trying to do an "if ( -e $OUT.out ) set x=$<", which will
|> wait for an ENTER before continuing with the program... The only thing is
|> that the "if ( -e )" statement (that searches for the existance of the file)
|> runs if there is an actual $OUT.out file or not...
In order to realize why this is happening, you have to keep in mind exactly
what $< is. In particular, it's a gross hack to do keyboard input using a
variable substitution. *Variable substition* is the key here. On a single
line "if" statement in C-shell input, variable substitution happens on the
entire line *before* the boolean of the "if" statement is checked. Since the
$< hack is a variable substitution, the shell reads a line of input in order
to put a value in place of $< *before* it checks if the boolean is true.
The fix is simple. Change your script to read:
if ( -e $OUT.out) then
set x=$<
endif
In fact, a large portion of your script can be enclosed in that if statement.
Rather than checking if $OUT.out exists before each line of the warning is
printed, you can do:
if ( -e $OUT.out ) then
clear
echo '******************************************************'
echo 'You have a leftover '$OUT'.out file. Since '$PROG''
echo 'will end up choking on this leftover file, I am going'
echo 'to delete it for you. If you do not want me to'
echo 'delete it, hit ^C, ENTER, and rename it to a different'
echo ' filename.'
echo '******************************************************'
echo ' '
echo ' If you want it deleted, press ENTER now to continue.'
set x=$<
rm $OUT.out
endif
--
Jonathan Kamens jik at CATS.UCSC.EDU
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