dbx: a plea for help -- HELP!
Mark Rosenthal
mbr at aoa.UUCP
Sat Mar 29 11:07:15 AEST 1986
It appears that most vendors have given up on 'sdb' in favor of 'dbx' or
some derivative of 'dbx'. I find that although 'dbx' is generally more
powerful than 'sdb' it lacks some capabilities that I depend on quite
heavily. If anyone is familiar with how to do the following with 'dbx',
please let me know. You will earn my undying gratitude.
By the way, I am running 'dbx' on a Sun workstation.
1. I'd like to be able to specify the format in which a variable is to be
displayed. If I have a variable (char *cp), I could do the following
with 'sdb':
me: cp/x or: cp/s or: cp/
sdb: 0x7fff3ec string string
With 'dbx', the dialogue is something like:
me: print cp
dbx: 0x7fff3ec
me: 0x7fff3ec/s
dbx: string
Having to type back into dbx what it just typed at me is a pain.
2. The man page for 'dbx' claims that the command to display a memory location
is:
[address] / [count] [mode]
where everything but the "/" is optional, and that "if no address is
specified, the address following the one displayed most recently is used".
Unfortunately, there is also a "/" command which searches the source file
for a string. Typing "/" reports:
"No saved search string"
rather than showing me the next location. This makes it quite a chore to
examine an array. Arrays of structures are even worse.
3. With 'sdb', I could display lines of code relative to the current line.
'dbx' appears to limit me to specifying absolute line numbers. This means
that anytime I hit a breakpoint and want to see some context, I have to
read the current line number from the screen, do some quick arithmetic,
and type "list from_line,to_line". The concentration required to do that
is a distraction from the problem I am trying to solve, namely finding and
fixing bugs in a program. A symbolic way of referencing dbx's line counter
would solve the problem, but I can find no mention of any such capability
in the documentation. I'd like to be able to do something like:
alias w list .-5,.+5
and then just type "w" to see context around the current line.
4. A common construct in C is a linked list of structures.
struct foo
{
struct foo *next;
int data;
char *moredata;
/* Etc., etc., etc. */
};
struct foo foobar;
Let's say my code malloc()s instances of foo, and links them in to the list
beginning at foobar. I am at a breakpoint, and I want to examine the list.
I don't remember the exact commands I used with sdb, but they went something
like:
Dialogue: Comments:
me: foobar/ show the value of foobar
sdb?: 0x7ff2ea
me: .->/ show what the last displayed value points at
(i.e. foobar->next)
sdb?: 0x7e3720
me: +/d show the next location in decimal
(i.e. foobar->data)
sdb?: 3
me: +/s show the next location as a string pointer
(i.e. foobar->moredata)
sdb?: string data
me: - back up one location (to foobar->data)
sdb?: 3
me: - back up one location (to foobar->next)
sdb?: 0x7e3720
me: .->/ show what the last displayed value points at
(i.e. foobar->next->next)
sdb?: 0x748238
me: +/d show the next location in decimal
(i.e. foobar->next->data)
sdb?: 2
me: +/s show the next location as a string pointer
(i.e. foobar->next->moredata)
sdb?: more chars
me: - back up one location (to foobar->next->data)
sdb?: 2
me: - back up one location (to foobar->next->next)
sdb?: 0x748238
me: .->/ show what the last displayed value points at
(i.e. foobar->next->next->next)
sdb?: 0 end of list
me: +/d show the next location in decimal
(i.e. foobar->next->next->data)
sdb?: 1
me: +/s show the next location as a string pointer
(i.e. foobar->next->next->moredata)
sdb?: still more chars
To do the same thing with dbx, the best I've been able to come up with
so far is:
Dialogue: Comments:
me: print foobar
dbx: 0x7ff2ea
me: print foobar->data
dbx: 3
me: print foobar->moredata
dbx: string data
me: print foobar->next
dbx: 0x7e3720 not zero - keep going
me: print foobar->next->data
dbx: 2
me: print foobar->next->moredata
dbx: more chars
me: print foobar->next->next
dbx: 0x748238 not zero - keep going
me: print foobar->next->next->data
dbx: 1
me: print foobar->next->next->moredata
dbx: still more chars
me: print foobar->next->next->next
dbx: 0 zero - end of list
Note that the sequence of commands I type to sdb is relatively simple,
and stays the same no matter how far through the list I've gone:
me: foobar/
me: .->/
me: +/d
me: +/s
me: -
me: -
me: .->/
me: +/d
me: +/s
me: -
me: -
me: .->/
me: +/d
me: +/s
whereas with dbx, I have to retype the entire sequence from the starting
point every time:
me: print foobar
me: print foobar->data
me: print foobar->moredata
me: print foobar->next
me: print foobar->next->data
me: print foobar->next->moredata
me: print foobar->next->next
me: print foobar->next->next->data
me: print foobar->next->next->moredata
me: print foobar->next->next->next
This makes a list of length 4 a pain to deal with, and a list of length 16
prohibitive. Linked lists with hundreds of elements are not uncommon.
Do the authors of 'dbx' really intend that I should have to type:
print foobar->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->next->data
to get to the 128'th (or did I only type next 127 times?) item in a list?
There MUST be a better way. Can somebody PLEASE enlighten me.
Sorry. I got a bit carried away there. I'll be alright in a second.
--
Mark of the Valley of Roses
...!{decvax,linus,ima,ihnp4}!bbncca!aoa!mbr
...!{wjh12,mit-vax}!biomed!aoa!mbr
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