Why isn't argv[argc]==(char *)0 ?

[Christoph Kuenkel]

In article <1635 at ctisbv.cti-software.nl>, pim at cti-software.nl (Pim Zandbergen) writes:
> guy at auspex.auspex.com (Guy Harris) writes:
> >(I.e., unless you have to deal with an archaic UNIX or a Mutant UNIX
> >From Hell, you can count on argv[argc] == 0.)
> 
> In X/OS, a SYSV/BSD hybrid operating system for the Olivetti LSX
> minicomputers, a reference to argv[argc] will make your program dump core.
which is SVID conformant.  as mentioned before, the SVID does not say 
anything about argv[argc] but states that

	"argc is the argument count, argv is an array of character pointers
	 to the argument themselves"

thus *(argv[argc]) may legally dump core.
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