nested loops
Gilles Courcoux
gilles at pase60.Convergent.Com
Sat Aug 11 02:15:51 AEST 1990
In article <4103 at herbie.misemi> you wrote:
>The problem lies in the $`echo $i` statment
Right, double variable expansion like that is resolved through the use
of the eval(1) command as in :
eval echo '$'$i
When the shell read the command, it expands it into
eval echo $them # the first time !
and then eval(1) do his job : evaluating its arguments, including
variables expansion and then execute the command which is by now :
echo one two three
The echo(1) command is needed because eval(1) then exec(2)utes its
first argument.
Your script become :
this="one two three"
that="four five six seven"
them="eight nine ten"
all="this that them"
#
for i in $all
do
for j in `eval echo '$'$i`
do
echo $i $j
done
done
Have a nice day,
Gilles Courcoux E-mail: sun!pyramid!ctnews!pase60!gilles
Unisys Network Computing Group Phone: (408) 435-7692
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