Question on the initialization of an interrupt vector in C
S.NURENBERG
4341shn at houxn.UUCP
Thu Aug 18 00:55:28 AEST 1983
I have a C question. I want to initialize some interrupt
vectors on a M68000 processor card so that when the
one board programmable timer causes an interrupt, it will
be serviced. Below is the current way I do it (which works).
What I want to know is why another way doesn't (see below):
typedef long *P_ADDR;
#define PTMVEC 0x78
main()
{
extern void clock();
P_ADDR *evec_ptr;
evec_ptr = (P_ADDR *) PTMVEC;
*evec_ptr =(P_ADDR) clock;
}
What I want to know is why the following line is syntactically
incorrect (as far as cc says so) but seems to me logically more
correct?
typdef void (*)() P_ADDR;
I appreciate any insight into this problem.
Steven Nurenbeg
houxn!4341shn
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