Changing .zoo archive to .lzh archive: help!
uunet!bria!mike
uunet!bria!mike
Sun Feb 17 15:54:20 AEST 1991
In an article, cs.arizona.edu!dave (Dave P. Schaumann) writes:
>
>I am trying to write a script that will allow me to convert zoo archives
>to lharc archives under Unix. Here's what I have so far:
>
>mkdir xxx
>cd xxx
>zoo xq// ../$1.zoo
>lharc aq ../$1.lzh * `no-dot .*`
>cd ..
>rm -r xxx
>
>Where "no-dot" is a simple program that echos back everything in argv[] that
>isn't "." or ".."
Actually, you can use ``find'' for this purpose ...
lharc aq ../$lzh `find . \( ! -name "." -a ! -name ".." \) -print`
So, how about this snippet ...?
--- snip --- snip --- snip --- snip --- snip --- snip --- snip --- snip ---
dir=.dir$$
mkdir $dir || exit
for archive in $*; do
cd $dir
zoo xq// ../${archive}.zoo
lharc aq ../${archive}.lzh `find . \( ! -name "." -a ! -name ".." \) -print`
cd ..
rm -fr $dir
mkdir $dir || exit
done
rm -fr $dir
--- snip --- snip --- snip --- snip --- snip --- snip --- snip --- snip ---
>Now, I could write a program to generate a temporary directory name using
>getpid() and some unlikely template, like "xx-######-temp". What I need to
>know is:
>
> 1. Is it a reasonable assumption that no two concurrent getpid()'s will
> return the same value?
It is _very_ reasonable to assume this. Updates to the kernel proc table
are atomic, insuring that no two "concurrent" processes have the same PID.
Hope this helps.
Cheers,
--
Michael Stefanik, MGI Inc., Los Angeles| Opinions stated are not even my own.
Title of the week: Systems Engineer | UUCP: ...!uunet!bria!mike
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